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[quote=JohnHell]
Let me say something, because I think this could be confusing if someone doesn't read correctly. I hope you aren't using the same code as I posted before, I mean, using the same conditional three times. Let me post an expanded code:

$a = [u]$b != $c[/u] ? $d : [u]$b != $c[/u] ? $d : [u]$b != $c[/u] ? $d : $x;
THE ABOVE IS WRONG TO USE AS CONDITIONAL, JUST WAS AN EXAMPLE OF WHAT I MEAN WITH MORE THAN ONE NEGATION USE

This is only to put values to the code, nothing else.
$a = 0;
$b = 1;
$c = 2;
$d = 3;
$x = 4;
$y = 5;

$a = [u]$b != $c[/u] ? $y : [u]$b != $d[/u] ? $y : [u]$c != $d[/u] ? $y : $x;
THE ABOVE IS CORRECT NOW

First condition: $a should take the value of $y if  $b is not equal to $c, correct. The result is that $a now is 5.

Second condition: $a should take the value of $y if  $b is not equal to $d, correct. The result is that $a now is 5.

Third condition: $a should take the value of $y if  $c is not equal to $d, correct. The result is that $a now is 5.

If not of the above: $a now is 4

Ok, what I came here with, is that no one of the three conditions are used and $a ever takes the value of $y, even if in the first condition, $b is  equal to $c, in the second, $b is equal to $d and in the third, $c is equal to $d, never is taken $x for a value for $a.

But, if instead 3 negative conditions, only one of the conditions is negative, all works.

So, what I was telling is that 3 negative conditions one "behind" another, doesn't work.[/quote]

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